關(guān)于數(shù)組IFS 設(shè)置問題.求大神指點

qimuzhi

1. #!/bin/bash -
   
2. 
   
3. OLD_IFS="$IFS"
   
4. IFS=","
   
5. arr=(
   
6. a,
   
7. bb bb,
   
8. cccc
   
9. )
   
10. for s in ${arr[@]}
    
11. do
    
12.     echo "$s"
    
13. done
    
14. IFS="$OLD_IFS"

復(fù)制代碼

=============實際的輸出==============

1. ~/tmp/shell/ifs $ ./a.sh
   
2. a
   
3. 
   
4. bb
   
5. bb
   
6. 
   
7. cccc
   
8. ~/tmp/shell/ifs $

復(fù)制代碼

=============OUT==============

我想要的是:
=============OUT==============
a
bb bb
cccc
=============OUT==============

求大神指點,我想以逗號為數(shù)組的分隔符號,但是不行.這是為什么啊?

扯淡的青春要扯淡對待

bash中應(yīng)該不支持二維數(shù)組吧，，
+ LD_IFS='
'
+ IFS=',
'
+ arr=(a, bb bb, cccc)
+ for s in '${arr[@]}'
+ echo a
a
+ for s in '${arr[@]}'
+ echo ''

+ for s in '${arr[@]}'
+ echo bb
bb
+ for s in '${arr[@]}'
+ echo bb
bb
+ for s in '${arr[@]}'
+ echo ''

+ for s in '${arr[@]}'
+ echo cccc
cccc
+ IFS=

要實現(xiàn)以上結(jié)果：
LD_IFS=$IFS
IFS=$',\n'
mm="
a,
bb bb,
cccc
"
arr=($mm)
for s in ${arr[@]}
do
    echo "$s"
done
IFS="$OLD_IFS"

yjh777

IFS 不會影響 () 里面的分割解析;

用 read -a :
    IFS="," read -a a <<< "a,bb bb,cccc"