請教awk指定輸出顯示行的問題

robinhappiness

$cat read.csv
#data
#filename,systemname,id,number
a1,apple,1,12345
a2,banana,2,67890
a3,pear,3,112345

awk -F, -vd="$(date '+%F %T')" -vh="$(hostname)" -vn="$(basename $0)" '$3!=$4{print d,h,n":",$1,"id and number are different."}' read.csv > syslog.csv

執(zhí)行后結(jié)果：
$cat syslog.csv
2015-09-30 13:00:00 test.sh: systemname id and number are different.
2015-09-30 13:00:00 test.sh: a1 id and number are different.
2015-09-30 13:00:00 test.sh: a2 id and number are different.
2015-09-30 13:00:00 test.sh: a3 id and number are different.

想在輸出的時候不顯示read.csv中注釋掉的前兩行的列名，
想得到如下輸出結(jié)果，應(yīng)該怎樣修改這個命令?
$cat syslog.csv
2015-09-30 13:00:00 test.sh: a1 id and number are different.
2015-09-30 13:00:00 test.sh: a2 id and number are different.
2015-09-30 13:00:00 test.sh: a3 id and number are different.

songyc_2015

awk -F, -vd="$(date '+%F %T')" -vh="$(hostname)" -vn="$(basename $0)" '$3!=$4&&!/^#/{print d,h,n":",$1,"id and number are different."}' read.csv > syslog.csv,是這意思么?

jason680

回復(fù) 1# robinhappiness


$ awk -v... '/^#/{next}...'
or
$ awk -v... '/^[ \t]*#/{next}...'

robinhappiness

songyc_2015 發(fā)表于 2015-09-30 14:16
awk -F, -vd="$(date '+%F %T')" -vh="$(hostname)" -vn="$(basename $0)" '$3!=$4&&!/^#/{print d,h,n":", ...

謝謝！
是這個意思！

robinhappiness

回復(fù) 3# jason680


    謝謝！

請教以下寫法中的 ...部分是什么意思？
$ awk -v... '/^#/{next}...'
or
$ awk -v... '/^[ \t]*#/{next}...'

robinhappiness

$ awk -v... '/^#/{next}...'
or
$ awk -v... '/^[ \t]*#/{next}...'

請教以上命令應(yīng)該怎樣加到如下命令中?多謝！

awk -F, -vd="$(date '+%F %T')" -vh="$(hostname)" -vn="$(basename $0)" '$3!=$4{print d,h,n":",$1,"id and number are different."}' read.csv > syslog.csv