求教list的remove方法

amandaysu

1
>>> c=['s1','s2']
>>> c
['s1', 's2']
>>> c.remove('s1')
>>> c
['s2']

2
>>> print ['s1','s2'].remove('s2')

求教一下1和2的區(qū)別在哪里，為什么我用第二種方式得到的是None？

bskay

你做的只是相當(dāng)于下面這樣的



1
>>> c=['s1','s2']
>>> c
['s1', 's2']
>>> c.remove('s1')

2
>>> print ['s1','s2'].remove('s2')

amandaysu

沒明白
回復(fù) 2# bskay


   

HH106

1. Syntax
   
2. Following is the syntax for remove() method:
   
3. 
   
4. list.remove(obj)
   
5. Parameters
   
6. obj -- This is the object to be removed from the list.
   
7. 
   
8. Return Value
   
9. This method does not return any value but removes the given object from the list.

復(fù)制代碼

amandaysu

thanks回復(fù) 4# HH106


   

reyleon

列表對象的方法都是在 "原處"  進(jìn)行修改的!

szerr

['s1','s2'].remove('s2') 沒有返回值，所以沒輸出。

jixuuse

Python 2.7.6 (default, Nov 10 2013, 19:24:24) [MSC v.1500 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> x=['s1','s2']
>>> x
['s1', 's2']
>>> x.remove('s2')
>>> x
['s1']
>>>