請教 []里如何區(qū)別開兩個正則表達式

tasteoftime_90

舉個例子：
[[[:space:]]*[[:lower:]]+[[:space:]]*\n]
[[:space:]]*[[:lower:]]+[[:space:]]*和\n區(qū)分開

謝啦！

bulletmarquis

回復 1# tasteoftime_90


    你例子里初始的[]就沒看懂，[]里面的*+有效果么？

   有具體場景不？

jason680

回復 1# tasteoftime_90

正則表達式學習筆記
http://www.72891.cn/forum.p ... mp;fromuid=24785593

yestreenstars

騷年，說說你的原始需求吧~

Herowinter

回復 1# tasteoftime_90

說說你到底想干什么吧?感覺可能不需要去繞
這兩個正則.

   

blackold

回復 4# yestreenstars


   

yestreenstars

黑哥，你為何如此調(diào)皮？{:3_182:}
回復 6# blackold


   

tasteoftime_90

啊 對哦 忘了[]里面元字符無意義這塊 就是想弄明白兩行空白是哪里來的而已
[try@KeepTry patrol]$ cat try.txt
123 abc 456 def
abc 123 def 456
[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*"}{print $0}' try.txt
123
456

123
456

[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*"}{print RT}' try.txt
abc
def

abc
def

[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*";ORS="|"}{print $0}' try.txt
123|456||123|456
|[try@KeepTry patrol]$
[try@KeepTry patrol]$ awk 'BEGIN{RS="([[:space:]]*[[:lower:]]+[[:space:]]*|\n)"}{print $0}' try.txt
123
456

123
456

回復 2# bulletmarquis


   

tasteoftime_90

木有原始訴求 瞎弄 就是想弄明白兩行空白是哪里來的而已
[try@KeepTry patrol]$ cat try.txt
123 abc 456 def
abc 123 def 456
[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*"}{print $0}' try.txt
123
456

123
456

[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*"}{print RT}' try.txt
abc
def

abc
def

[try@KeepTry patrol]$ awk 'BEGIN{RS="[[:space:]]*[[:lower:]]+[[:space:]]*";ORS="|"}{print $0}' try.txt
123|456||123|456
|[try@KeepTry patrol]$
[try@KeepTry patrol]$ awk 'BEGIN{RS="([[:space:]]*[[:lower:]]+[[:space:]]*|\n)"}{print $0}' try.txt
123
456

123
456
回復 4# yestreenstars


   

bulletmarquis

回復 8# tasteoftime_90


    空行是因為你改了RS，導致原先兩行文本中的\n，不再是RT了。。。