正則表達(dá)式如何排除有兩個(gè)連續(xù)字符的匹配?

jason680

回復(fù) 10# rdcwayx

There is a simple way to do that in Perl

# perl -lape 's/{#.*?#}/+/g' file
1. +
2. +
3. +a#}
fdss+fdjsf+dfs
fdss+fdjsf+dfs
fdss+dfs
fdss+fdjsf+dfs
fdss+fdjsf+dfs
fdss+fdjsf+dfs

   

rdcwayx

jason680 發(fā)表于 2014-03-06 08:33
回復(fù) 10# rdcwayx

There is a simple way to do that in Perl

這個(gè)問號(hào)用的很到位。沒有問號(hào)，就是貪婪(greedy)匹配， 用了問號(hào)，就是懶惰(lazy)匹配或者非貪婪匹配。

Herowinter

@kaize0409@jason680@rdcwayx
如果你要一個(gè)正則實(shí)現(xiàn)懶惰匹配，你可以參考版主和Jason的perl代碼；
如果你非要在awk中實(shí)現(xiàn)，你可以參考下面的代碼，不過這種做法擴(kuò)展
性不是很好，僅僅針對(duì)你這個(gè)問題。

1. awk '{s="";while((start=match($0,/{#/))>0){end=match($0,/#}/);if(end>start){s=s""substr($0,1,start-1)"+";$0=substr($0,end+2)}else break};print s$0}' i
   
2. 
   
3. +
   
4. +
   
5. +a#}
   
6. fdss+fdjsf+dfs
   
7. fdss+fdjsf+dfs
   
8. fdss+dfs
   
9. fdss+fdjsf+dfs
   
10. fdss+fdjsf+dfs
    
11. fdss+fdjsf+dfs
    
12. fff{#
    
13. ggg#}
    
14. hhhrrrr
    

復(fù)制代碼

1. cat i
   
2. {#a#a#}
   
3. {#a}a#}
   
4. {#a#}a#}
   
5. fdss{#sdjas#}fdjsf{#dsfjs#}dfs
   
6. fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
   
7. fdss{#sdjas#fdjsf#dsfjs#}dfs
   
8. fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
   
9. fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
   
10. fdss{#sdjas#}fdjsf{#dsfjs#}dfs
    
11. fff{#
    
12. ggg#}
    
13. hhhrrrr

復(fù)制代碼

rogantianwz

*? 這種忽略優(yōu)先量詞的用法在很多地方都不支持，但我估計(jì)perl、java、php什么的應(yīng)該是支持的
因?yàn)槲以贚Z的另外一個(gè)帖子里，他用的是awk，我測(cè)了一下，貌似不支持*?

me09

1. #!/bin/bash
   
2. while read line
   
3. do
   
4.         echo `echo $line|tr  "^[#{}]"  "\n"|awk 'BEGIN{RS="[\n]+";ORS=" "}{print $0}'|sed 's/+$/\n/'`
   
5. done
   

復(fù)制代碼

cat x.txt
1. {#a#a#}
2. {#a}a#}
3. {#a#}a#}
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#fdjsf#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#}fdjsf{#dsfjs#}dfs

運(yùn)行：bash x.sh < x.txt
1. a a
2. a a
3. a a
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs

me09

1. #!/bin/bash
   
2. while read line
   
3. do
   
4.         echo `echo $line|tr  "^[#{}]"  "\n"|awk 'BEGIN{RS="[\n]+";ORS=" "}{print $0}'|sed 's/+$/\n/'`
   
5. done
   

復(fù)制代碼

cat x.txt
1. {#a#a#}
2. {#a}a#}
3. {#a#}a#}
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#fdjsf#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#}fdjsf{#dsfjs#}dfs

運(yùn)行：bash x.sh < x.txt
1. a a
2. a a
3. a a
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs

me09

1. #!/bin/bash
   
2. while read line
   
3. do
   
4.         echo `echo $line|tr  "[ #{}]"  "\n"|awk 'BEGIN{RS="[\n]+";ORS="+"}{print $0}'|sed 's/+$/\n/'`
   
5. done

復(fù)制代碼

cat x.txt
1. {#a#a#}
2. {#a}a#}
3. {#a#}a#}
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#fdjsf#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
------------------------------------------------------
sh x.sh < x.txt
1.+a+a
2.+a+a
3.+a+a
fdss+sdjas+fdjsf+dsfjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sdjas+fdjsf+dsfjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sdjas+fdjsf+dsfjs+dfs