這個(gè)awk語句可以合并嗎

beacon1024

目的是取出，號(hào)分隔部分中的第二個(gè)括號(hào)中的servername。
不能可以寫到一個(gè)awk語句中呢？
各位前輩幫忙優(yōu)化一下啦。
謝謝！
#awk -F"," '{printf $1 "\n" $2 "\n"}' temp |awk -F"[)(]" '{print $4}'
abc-v2-app3
abc-wwwssl143
abc-v3-app17
abc-wsgwssl2
efg-wwwssl144
efg-wsauthssl2
abc-www425
abc-opapi1
efg-wsapissl8
efg-v1-app5
abc-www427
abc-v2-app12
abc-www407
efg-v3-app17
abc-www452
abc-v1-app15
efg-wsgwssl7
abc-v5-app9
abc-www422
efg-v2-app9


#cat temp
(Component) sudoers-file-Audit-Server (abc-v2-app3),
(Component) sudoers-file-Audit-Server (abc-wwwssl143), (Component) sudoers-file-Audit-Server (abc-v3-app17),
(Component) sudoers-file-Audit-Server (abc-wsgwssl2), (Component) sudoers-file-Audit-Server (efg-wwwssl144),
(Component) sudoers-file-Audit-Server (efg-wsauthssl2), (Component) sudoers-file-Audit-Server (abc-www425),
(Component) sudoers-file-Audit-Server (abc-opapi1), (Component) sudoers-file-Audit-Server (efg-wsapissl,
(Component) sudoers-file-Audit-Server (efg-v1-app5), (Component) sudoers-file-Audit-Server (abc-www427),
(Component) sudoers-file-Audit-Server (abc-v2-app12), (Component) sudoers-file-Audit-Server (abc-www407),
(Component) sudoers-file-Audit-Server (efg-v3-app17), (Component) sudoers-file-Audit-Server (abc-www452),
(Component) sudoers-file-Audit-Server (abc-v1-app15), (Component) sudoers-file-Audit-Server (efg-wsgwssl7)

wtuter

回復(fù) 1# beacon1024


    awk -F'(' '{print $NF|"tr \"[),]\" \" \""}'

beacon1024

謝謝wtuter啊，神人真多啊。完全看不懂的句子，我得好好學(xué)習(xí)

beacon1024

回復(fù) 2# wtuter


   
awk -F"," '{printf $1 "\n" $2 "\n"}' temp |awk -F"[)(]" '{print $4}'  | wc -l
68
awk -F'(' '{print $NF|"tr \"[),]\" \" \""}' job  | wc -l
34

不對(duì)啊，少了一半的記錄，后面一行沒有打出來。

jason680

目的是取出，號(hào)分隔部分中的第二個(gè)括號(hào)中的servername。
不能可以寫到一個(gè)awk語句中呢？
各位前輩幫忙優(yōu)化 ...
beacon1024 發(fā)表于 2011-07-01 10:58

awk -F'[)(]' '{n=4;while($n){print $n;n+=4}}' temp

ywlscpl

awk -F, '{split($1,m1,"[)(]");split($2,m2,"[)(]");print m1[4]"\n"m2[4]}' file

bbgg1983

1. awk '{gsub(/.*\(|\)/,"")}1' RS=, file

復(fù)制代碼

251995427

awk -v RS="," -F "[()]" '{print $4}' d