AWK如何處理N多列的列參數(shù)？

hosyp

我有個文件有幾百列不定，要得到其中指定列，已求出指定列的列數(shù)，是一個字符串，如“$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18”，
如何讓AWK調(diào)用它？
用aa=“$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18”, awk '{print aaa}' aaa=$aa source.txt 只能得到如下結果，而不是我要的值：
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,
$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18,

justlooks

直接awk '{print $1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18}' 不行？

hosyp

事先不知道是哪幾個列呀，這是算出來的呀
有一個設置文件存的是所有需要的列，我用shell找出需要列在源文件中的列號，得出這么個字符串，換個源文件列號就變了

wtuter

回復 1# hosyp


    aa=“1,2,9,11,91,4,5,25,99，6,18”, awk '{print $aaa}' aaa=$aa source.txt

beginner-bj

這樣的問題，用eval。

hosyp

回復 4# wtuter


    這樣不行，只能打出第一列

ywlscpl

a='$1,$2,$9,$11,$91,$4,$5,$25,,$99,$6,$18'
awk "{print $a}" file

hosyp

我試了一下，用如下語句可以：
aa='$1,$2,$9,$11,$91,$4,$5,$25,$99,$6,$18'
echo '{print '$aa'}'>progfile
awk -F, -f progfile source.txt

iori809

恩沒錯~ 解決思路就是 絕對引用和部分引用的區(qū)別