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標(biāo)題:
php如何取得select * 返回的結(jié)果
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作者:
alenbull
時(shí)間:
2009-04-14 18:56
標(biāo)題:
php如何取得select * 返回的結(jié)果
mysql> select * from user;
+-----+-----------+------------+
| uid | username | password |
+-----+-----------+------------+
| 1 | test | test |
| 2 | test1 | test1 |
| 3 | test2 | test2 |
$sql = "select username,password from user";
$d=mysql_query($sql);
$e=mysql_fetch_array($d);
echo $e['0'],$e['1'];
只能取出第一行,請(qǐng)高手指點(diǎn)
作者:
bs
時(shí)間:
2009-04-14 19:07
while ($e= mysql_fetch_array(mysql_fetch_array($d))) {
echo $e['0'],$e['1'];
}
作者:
alenbull
時(shí)間:
2009-04-14 19:16
謝謝樓上的朋友回復(fù).但是運(yùn)行錯(cuò)誤.Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource
作者:
alenbull
時(shí)間:
2009-04-14 19:31
好了.
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
printf ("ID: %s Name: %s\n", $row[0], $row[1]);
}
mysql_free_result($result);
作者:
bs
時(shí)間:
2009-04-15 08:59
我汗
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